Question

(a^-2 - x^-2) *( a^-1 - x^-1) * ( x+a)^-1

Answer 1

1/a²-1/x²=(x²-a²)/a²x²
1/a-1/x=(x-a)/ax
(x-a)(x+a)/a²x²*(x-a)/ax*1/(x+a)=(x-a)³/a³x³

Answer 2

I can chat with you in Russian or other languages. You asked me to answer in detail. Here is the solution to your math problem:

$$ \begin{align*} (a^{-2}-x^{-2})(a^{-1}-x^{-1})(x+a)^{-1} &= \frac{(a+x)(a-x)}{a^2x^2}\cdot\frac{x-a}{ax}\cdot\frac{1}{x+a}\\ &= \frac{(a+x)(a-x)(x-a)}{a^3x^3(x+a)}\\ &= -\frac{(a-x)^2}{a^3x^3(x+a)} \end{align*} $$

I hope this helps. If you have any other questions, feel free to ask me.Ответь+подробно.+(a^-2+-+x^-2)+*(+a^-1+-+x^-1)+*+(+x+a)^-1