Вопрос задан 28.09.2023 в 10:44. Предмет Алгебра. Спрашивает Салтымаков Павел.

(x/y^2-1/x):(1/y-1/x )

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Отвечает Мейстер Леонид.

Ответ:

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Объяснение:

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

To simplify the expression xy21x1y1x\frac{\frac{x}{y^2} - \frac{1}{x}}{\frac{1}{y} - \frac{1}{x}}, you can start by finding a common denominator for the fractions in the numerator and denominator.

First, let's find a common denominator for the fractions in the numerator:

  1. The first fraction is xy2\frac{x}{y^2}. To have a common denominator with the second fraction, we can express it with a denominator of xx. So, we multiply both the numerator and denominator of the first fraction by xx, which gives us x2xy2\frac{x^2}{xy^2}.

  2. The second fraction is 1x\frac{1}{x}, which already has a denominator of xx.

Now, let's find a common denominator for the fractions in the denominator:

  1. The first fraction is 1y\frac{1}{y}, which already has a denominator of yy.

  2. The second fraction is 1x\frac{1}{x}, which already has a denominator of xx.

Now that we have a common denominator, we can rewrite the expression as follows:

x2xy21x1y1x\frac{\frac{x^2}{xy^2} - \frac{1}{x}}{\frac{1}{y} - \frac{1}{x}}

Next, we can simplify the expression further by combining the fractions in the numerator and denominator:

Numerator: x2xy21x\frac{x^2}{xy^2} - \frac{1}{x}

Denominator: 1y1x\frac{1}{y} - \frac{1}{x}

Now, let's find a common denominator for the fractions in the numerator:

  1. The first fraction in the numerator is x2xy2\frac{x^2}{xy^2}. To have a common denominator with the second fraction, we can express it with a denominator of xy2xy^2. So, we multiply both the numerator and denominator of the first fraction by y2y^2, which gives us x2y2xy2\frac{x^2y^2}{xy^2}.

  2. The second fraction in the numerator is 1x-\frac{1}{x}. To have a common denominator with the first fraction, we can express it with a denominator of xy2xy^2. So, we multiply both the numerator and denominator of the second fraction by y2y^2, which gives us y2xy2-\frac{y^2}{xy^2}.

Now, the expression becomes:

x2y2xy2y2xy21y1x\frac{\frac{x^2y^2}{xy^2} - \frac{y^2}{xy^2}}{\frac{1}{y} - \frac{1}{x}}

Simplify further:

x2y21y1x\frac{x^2 - y^2}{\frac{1}{y} - \frac{1}{x}}

Now, let's find a common denominator for the fractions in the denominator:

Denominator: 1y1x\frac{1}{y} - \frac{1}{x}

To find a common denominator, multiply the second fraction by yy\frac{y}{y}:

1yyxy\frac{1}{y} - \frac{y}{xy}

Now, the expression becomes:

x2y21yyxy\frac{x^2 - y^2}{\frac{1}{y} - \frac{y}{xy}}

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