Question

(3x³-2x²y):x²-(2xy²+x²y):(⅓xy)​

Answer 1

Ответ примера на фотке написан

Answer 2

Let's simplify the given expression step by step:

Expression: (3x³ - 2x²y) / x² - (2xy² + x²y) / (⅓xy)

Step 1: Simplify the terms in the numerators and denominators separately.

Numerator 1: 3x³ - 2x²y

Numerator 2: -(2xy² + x²y) = -2xy² - x²y

Denominator: x² - (2xy² + x²y) / (⅓xy)

Step 2: Combine the numerators.

Combined numerator: 3x³ - 2x²y - 2xy² - x²y

Step 3: Combine like terms in the numerator.

Combined numerator: 3x³ - 3x²y - 2xy²

Step 4: Simplify the denominator.

Denominator: x² - (2xy² + x²y) / (⅓xy)

Step 5: Simplify the fraction by dividing the combined numerator by the denominator.

$\frac{{3x³ - 3x²y - 2xy²}}{{x² - (2xy² + x²y) / (⅓xy)}}$

$\frac{{3x³ - 3x²y - 2xy²}}{{x² - \frac{{2xy² + x²y}}{{⅓xy}}}}$

$\frac{{3x³ - 3x²y - 2xy²}}{{x² - \frac{{2xy²}}{{⅓xy}} - \frac{{x²y}}{{⅓xy}}}}$

$\frac{{3x³ - 3x²y - 2xy²}}{{x² - \frac{{2}}{{3}} - \frac{{x}}{{3}}}}$

$\frac{{3x³ - 3x²y - 2xy²}}{{x² - \frac{{2 + x}}{{3}}}}$