Question

(t + 1)(t ^ 2 - t + 1) =​

Answer 1

Ответ:

(t+1)(t²-t+1)=t³+1³=t³+1.

Объяснение:

свернули выражение по формуле

суммы кубов

(а+б)(а²-аб+б²)=а³+б³.

Answer 2

Ответ:

t^3 + 1

Объяснение:

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Answer 3

To expand the expression (t + 1)(t^2 - t + 1), you can use the distributive property (also known as FOIL). Here's how you can do it step by step:

(t + 1)(t^2 - t + 1)

Step 1: Multiply t by each term inside the second parentheses:

t * t^2 = t^3 t * (-t) = -t^2 t * 1 = t

So, after multiplying t by each term inside the second parentheses, you get:

t^3 - t^2 + t

Step 2: Multiply 1 by each term inside the second parentheses:

1 * t^2 = t^2 1 * (-t) = -t 1 * 1 = 1

So, after multiplying 1 by each term inside the second parentheses, you get:

t^2 - t + 1

Now, you have the results of both Step 1 and Step 2:

t^3 - t^2 + t + t^2 - t + 1

Step 3: Combine like terms:

The t^2 and -t^2 terms cancel each other out:

t^3 + t - t + 1

Now, simplify the expression:

t^3 + 1

So, the expanded form of the expression (t + 1)(t^2 - t + 1) is:

t^3 + 1