Question

1)(х-2)(|х|+2)=0 2)7(3х+1)-19х=-11

Answer 1

Объяснение:

1)x-2=0. [x]+2=0

x1=2. [x]=-2

• нет решений

2) 7(3x+1)-19x=-11

21x+7-19x=-11

21x-19x=-11-7

2x=-18

x=-9

Answer 2

Let's solve the given equations step by step:

1. (x-2)(|x|+2) = 0

To solve this equation, you can split it into two cases:

Case 1: (x - 2) = 0 x - 2 = 0 x = 2

Case 2: (|x| + 2) = 0 This case means |x| + 2 = 0, but absolute values are always non-negative, so there is no real number solution for this case.

So, the only real solution for the equation is x = 2.

2. 7(3x + 1) - 19x = -11

First, distribute the 7 on the left side:

21x + 7 - 19x = -11

Now, combine like terms by subtracting 7 from both sides:

21x - 19x + 7 = -11 - 7

2x + 7 = -18

Now, subtract 7 from both sides:

2x + 7 - 7 = -18 - 7

2x = -25

Finally, divide both sides by 2 to isolate x:

2x/2 = -25/2

x = -25/2

So, the solution to the second equation is x = -25/2 or -12.5.