Вопрос задан 23.09.2023 в 14:46. Предмет Алгебра. Спрашивает Кусакина Света.

1. Яка з пар чисел є розв’язком системи координат:(3;4),(5;2),(6;3),(7;0) . {х+у=7, х-у=3. 2.

Розв’яжіть систему рівнянь способом підстановки:{2х-у+6=0, 2х+у=10. 3.Побудуйте графік рівняння:4х+у=-4. Посмотреть ответы Скільки балів даєте? 20 а там не написано sswkxq sswkxq Ответ: 1) (5;2) 2 и 3 на фото пожалуйста зайди в мой профиль там 2 часть пж skkcanonh skkcanonh Фотографія до третього завдання Объяснение: 1. {х+у=7, х-у=3 (5;2) є розв'язком системи координат 2.{2х-у+6=0, 2х+у=10 способом підстановки, переставляємо змінні й числа(числа з протилежним знаком): будується система: {2х-у=-6 2х+у=10 підемо через у з першого рівняння і підставимо його одержане значення у друге рівняння: {у=2х-6 2х+2х-6=10 знову переносимо змінні й числа {у=2х-6 4х=16 з цього х - 4, й шукаємо у {х=4 у=2×4-6 у=2 (4;2). 3. Побудувати графік рівняння: 4х+у=-4. у= -4-4х х|-1|0| у|0|-4| 5 звёзд дякую, моглиб ви зробити 2 частину завання вона в мене в профілі Новые вопросы в Алгебра 2 / х-3 - 8х/2х+8 область допусьимых значений Отдаю половину всего банка тому кто решит мне здавать через 18 минут. Прошу помогите задача 1. Надо до завтра решить 7÷ х^2-9 Область допустимых значений Помогите пожалуйста, с полным решением) Буду очень блогодарна) Тема: Раціональні вирази. Раціональні дроби. ​ Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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  1. Розв'язок системи рівнянь {х+у=7, х-у=3} можна знайти шляхом додавання обох рівнянь. Отримаємо:

(х + у) + (х - у) = 7 + 3

2х = 10

Тепер поділімо обидві сторони на 2:

х = 5

Тепер, знаючи значення х, можемо підставити його в одне з рівнянь для знаходження у:

5 + у = 7

у = 7 - 5

у = 2

Отже, розв'язком системи є (5, 2).

  1. Для розв'язання системи рівнянь {2х-у+6=0, 2х+у=10} способом підстановки спершу можна вирішити одне з рівнянь на одну змінну і після цього підставити результат в інше рівняння.

Спочатку розв'яжемо перше рівняння на y:

2x - y + 6 = 0

y = 2x + 6

Тепер підставимо це значення y в друге рівняння:

2x + (2x + 6) = 10

4x + 6 = 10

4x = 10 - 6

4x = 4

x = 4 / 4

x = 1

Тепер, знаючи значення x, можемо знайти значення y, використовуючи перше рівняння:

2 * 1 - y + 6 = 0

2 - y + 6 = 0

-y + 8 = 0

-y = -8

y = 8

Отже, розв'язком системи є (1, 8).

  1. Для побудови графіка рівняння 4x + y = -4 спочатку перепишемо його у формі y = -4 - 4x.

Тепер ми можемо побудувати графік цього рівняння. Це лінійна функція, і вона буде мати наступний вигляд:

y = -4 - 4x

Для побудови графіка ви можете взяти декілька значень x, знайти відповідні значення y і намалювати точки на координатній площині. Наприклад:

  • Якщо x = 0, то y = -4 - 4 * 0 = -4, тобто точка (0, -4).
  • Якщо x = 1, то y = -4 - 4 * 1 = -8, тобто точка (1, -8).
  • Якщо x = -1, то y = -4 - 4 * (-1) = 0, тобто точка (-1, 0).

Після цього з'єднайте ці точки лінією, і ви отримаєте графік рівняння 4x + y = -4.

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