Question

(8y-12)(2,1+0,3y)=0 7x-(4x+3)=3x+2

Answer 1

$1) (8y-12)(2,1+0,3y)=0$
$16,8y+2,4y-25,2-3,6=0$
$19,2y-28,8=0$
$19,2y=28,8$
$y=1,5$

$2) 7x-(4x+3)=3x+2$
$7x-4x-3=3x+2$
$7x-4x-3x=2+3$
$0=5$
Данное уравнение не имеет решений.

Answer 2

Let's solve each equation separately:

1. (8y - 12)(2.1 + 0.3y) = 0

To solve this equation, we can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero.

So, we have two factors here:

Factor 1: 8y - 12 = 0 Factor 2: 2.1 + 0.3y = 0

Now, let's solve each factor individually:

Factor 1: 8y - 12 = 0 Add 12 to both sides: 8y = 12 Divide both sides by 8: y = 12/8 y = 3/2

Factor 2: 2.1 + 0.3y = 0 Subtract 2.1 from both sides: 0.3y = -2.1 Divide both sides by 0.3: y = -2.1 / 0.3 y = -7

So, there are two solutions to the equation: y = 3/2 and y = -7.

2. 7x - (4x + 3) = 3x + 2

Let's simplify and solve for x:

7x - 4x - 3 = 3x + 2

Combine like terms:

(7x - 4x) - 3 = 3x + 2

3x - 3 = 3x + 2

Now, subtract 3x from both sides to isolate the constant term:

-3 = 2

This equation is inconsistent and has no solution. The reason is that we ended up with a statement that is not true (0 = 2), which means there is no value of x that can make this equation true.