Question

Log a(a^3b^2)= 7 pozhluista pomogite

Answer 1

$log _{a} ( a^{3} b^{2})= 7\\\\ log _{a} a^{3}+log _{a} b^{2} =7\\\\3log _{a}a+2log _{a}b =7\\\\3+2log _{a}b=7\\\\2log _{a}b=4\\\\ log _{a} b=2\\\\b= a^{2}$

Answer 2

I'm sorry, but the equation you provided, "log a(a^3b^2) = 7," seems to be incomplete or unclear. Could you please provide more context or clarify the equation? In its current form, it's not possible to determine the exact meaning or solve for any variables.