Question

(7а+2б)^ -(3а-б) •(4а+5б) алгебра рішить

Answer 1

(7a+2b)-(3a-b)*(4a+5b)=

Answer 2

To simplify the given expression, we can start by expanding the expression (7а+2б)^-(3а-б) using the properties of exponents and then multiply the result by (4а+5б).

Step 1: Expanding (7а+2б)^-(3а-б) To expand (7а+2б)^-(3а-б), we use the rule that (a+b)^n = a^n + nC1 * a^(n-1)b + nC2 * a^(n-2)b^2 + ... + b^n, where nCk represents "n choose k" or binomial coefficients. In this case, n = -(3а-б).

(7а+2б)^-(3а-б) = (7а)^(-(3а-б)) + (-1)C1 * (7а)^(-(3а-б) - 1) * 2б + (-1)C2 * (7а)^(-(3а-б) - 2) * (2б)^2

Step 2: Simplify the terms

1. (7а)^(-(3а-б)) = 1 / (7а)^(3а-б)
2. (-1)C1 = -1
3. (-1)C2 = 1

So, the expanded expression becomes:

(7а+2б)^-(3а-б) = 1 / (7а)^(3а-б) - 2б / (7а)^(3а-б + 1) + 4б^2 / (7а)^(3а-б + 2)

Step 3: Multiply by (4а+5б) Now, multiply the above expression by (4а+5б):

[(7а+2б)^-(3а-б)] • (4а+5б) = (1 / (7а)^(3а-б) - 2б / (7а)^(3а-б + 1) + 4б^2 / (7а)^(3а-б + 2)) • (4а+5б)

To present the final result, it is important to note that the expression (7а+2б)^-(3а-б) may not simplify to a nice and neat expression, and it will still contain variables and complex terms. Therefore, we have shown the expanded form above. If there are any specific values for 'a' and 'b', we can further substitute them to obtain a numerical result. Otherwise, we leave it in the expanded form as shown.