Question

(c- 6c-9/c):(3/c - 1)=

Answer 1

(с-6с-9/с):(3/с-1) =

= (-7с-9/с):(3/с-1) =

= (-7с*с-9/с*с):(3/с*с-1*с) =

= (-7с^2-9):(3-с)

Answer 2

(c- 6c-9/c):(3/c - 1)=(-5с-9/с):3-с/с= -5с2-9/с * с/3-с= (-5с2-9)*1/3-с=-5с2-9/3-с= -5с2+9/3-с

Answer 3

To simplify the given expression, let's follow the order of operations (PEMDAS/BODMAS):

1. Parentheses/Brackets
2. Exponents/Orders
3. Multiplication and Division (from left to right)
4. Addition and Subtraction (from left to right)

The given expression is:

(c - 6c - 9) / (3/c - 1)

Step 1: Combine like terms in the numerator (c - 6c - 9): = (-5c - 9) / (3/c - 1)

Step 2: To divide by a fraction, we can multiply by its reciprocal. So, let's find the reciprocal of (3/c - 1), which is (1 / (3/c - 1)): = (-5c - 9) * (1 / (3/c - 1))

Step 3: Now, let's simplify the fraction in the denominator:

3/c - 1 To get a common denominator, multiply the second term (1) by (c / c):

(3/c) - (c/c) = (3/c) - c/c = (3 - c) / c

So, the expression becomes:

(-5c - 9) * (1 / ((3 - c) / c))

Step 4: To divide by a fraction, we can multiply by its reciprocal. The reciprocal of ((3 - c) / c) is (c / (3 - c)):

= (-5c - 9) * (c / (3 - c))

Step 5: Now, let's distribute the multiplication:

= (-5c^2 - 9c) / (3 - c)

So, the simplified expression is:

(-5c^2 - 9c) / (3 - c)