Question

16x^2-6x-1=0 Теорема Виета

Answer 1

Теорема Виета: x1=$\frac{-1}{8}$

x2=$\frac{1}{2}$

Answer 2

Вообщем Теорема Виета
х1+х2=6 (число с минусом возле х)
х1*х2=-1 (число без изменений без х)
И дальше метод подбора или решение системы уравнений
Так вот:
х1 = -1/8
х2 = 1/2

Answer 3

The Vieta's formulas, also known as Vieta's relations, are a set of mathematical equations that relate the coefficients of a polynomial to the sums and products of its roots. For a quadratic equation of the form:

ax^2 + bx + c = 0

The Vieta's formulas are given as follows:

1. Sum of the roots: The sum of the roots (denoted by α and β) is equal to the negation of the coefficient of the linear term (bx) divided by the coefficient of the quadratic term (a):

α + β = -b/a

2. Product of the roots: The product of the roots (α and β) is equal to the constant term (c) divided by the coefficient of the quadratic term (a):

α * β = c/a

For the equation you provided: 16x^2 - 6x - 1 = 0, we can identify the coefficients as follows:

a = 16 b = -6 c = -1

Now, let's apply the Vieta's formulas:

1. Sum of the roots (α + β) = -b/a = -(-6)/16 = 6/16 = 3/8
2. Product of the roots (α * β) = c/a = -1/16

So, for the quadratic equation 16x^2 - 6x - 1 = 0, the sum of the roots is 3/8, and the product of the roots is -1/16.