Question

Решить -18/(x+4)^2>=0

Answer 1

-18/(x+4)²≥0

решений нет, т.к. чтобы  это выражение было ≥0, надо,

чтобы (х+4)² был <0, а это невозможно, четная степень всегда ≥0

Answer 2

To solve the inequality $-\frac{18}{(x+4)^2} \geq 0$, we need to find the values of $x$ that satisfy this inequality.

Step 1: Find the critical points by setting the expression inside the parentheses equal to zero and solving for $x$: $(x+4)^2 = 0$

Taking the square root of both sides: $x+4 = 0$

Solving for $x$: $x = -4$

Step 2: Analyze the inequality in the intervals defined by the critical points and beyond:

Interval 1: $x < -4$ Choose $x = -5$ (a value less than -4) to test the inequality: $-\frac{18}{(-5+4)^2} = -18 \geq 0$ (False)

Interval 2: $x > -4$ Choose $x = 0$ (a value greater than -4) to test the inequality: $-\frac{18}{(0+4)^2} = -\frac{18}{16} = -\frac{9}{8} < 0$ (False)

Step 3: Combine the results The inequality $-\frac{18}{(x+4)^2} \geq 0$ is not satisfied for any real value of $x$.

Thus, there are no solutions for this inequality.