Question

3n(n+2)-(n+3)^2 help

Answer 1

Ответ:

$3n(n+2)-(n+3)^2=3n^2+6n-n^2-6n-9=2n^2-9$

Объяснение:

Answer 2

To simplify the expression 3n(n+2) - (n+3)^2, we can follow the order of operations (PEMDAS/BODMAS) and expand the squared term. Let's go step by step:

1. Expand the squared term (n+3)^2: (n+3)^2 = (n+3)(n+3) = n(n+3) + 3(n+3) = n^2 + 3n + 3n + 9 = n^2 + 6n + 9

2. Substitute the expanded squared term into the expression: 3n(n+2) - (n+3)^2 = 3n(n+2) - (n^2 + 6n + 9)

3. Distribute the 3n across the terms inside the parentheses: 3n(n+2) - (n^2 + 6n + 9) = 3n^2 + 6n - n^2 - 6n - 9

4. Combine like terms: (3n^2 - n^2) + (6n - 6n) - 9 = 2n^2 - 9

Therefore, the simplified expression is 2n^2 - 9.