Question

8xв квадрате -12x+36 =0

Answer 1

Ответ:

${8x}^{2} - 12x + 36 = 0 \\ d = 144 - 4 \times 36 \times 8 = - 1008$

Нет корней, т.к. D<0

Answer 2

To solve the quadratic equation 8x² - 12x + 36 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 8, b = -12, and c = 36. Substituting these values into the quadratic formula, we get:

x = (-(-12) ± √((-12)² - 4 * 8 * 36)) / (2 * 8) = (12 ± √(144 - 1152)) / 16 = (12 ± √(-1008)) / 16

Since the square root of a negative number is not a real number, it means this quadratic equation has no real solutions. The discriminant, which is the value inside the square root, is negative, indicating that the equation does not intersect the x-axis. Therefore, there are no real values of x that satisfy the equation 8x² - 12x + 36 = 0.