Question

X-1/x^3+3x^2+x+3 + 1/x^4-1 = x+2/x^3+3x^2-x-3

Answer 1

Ответ:

не знаю что именно нужно было сделать,поэтому только такое решение

Answer 2

To simplify the given expression, let's combine the fractions on both sides of the equation and find a common denominator:

We have:

X - 1/(x^3 + 3x^2 + x + 3) + 1/(x^4 - 1) = (x + 2)/(x^3 + 3x^2 - x - 3)

First, let's find the common denominator for the fractions on both sides. The common denominator will be (x^3 + 3x^2 + x + 3)(x^4 - 1) = (x^7 + 3x^6 + x^5 + 3x^4 - x^3 - 3x^2 - x - 3).

Now, let's rewrite the expression with the common denominator:

(x * (x^4 - 1) - (x^3 + 3x^2 + x + 3) + (x^3 + 3x^2 - x - 3)) / (x^7 + 3x^6 + x^5 + 3x^4 - x^3 - 3x^2 - x - 3)

Simplifying further:

(x^5 - x - x^3 - 3x^2 - 3 + x^3 + 3x^2 - x - 3) / (x^7 + 3x^6 + x^5 + 3x^4 - x^3 - 3x^2 - x - 3)

Combining like terms:

(x^5 - x + x^3 - x^3 - 3x^2 + 3x^2 - x - x - 3 - 3) / (x^7 + 3x^6 + x^5 + 3x^4 - x^3 - 3x^2 - x - 3)

Simplifying further:

(-4x - 6) / (x^7 + 3x^6 + x^5 + 3x^4 - x^3 - 3x^2 - x - 3)

Therefore, the simplified expression is (-4x - 6) / (x^7 + 3x^6 + x^5 + 3x^4 - x^3 - 3x^2 - x - 3).