Question

(x-3)²+3x=3x(x-3)..........​

Answer 1

${(x - 3)}^{2} + 3x = 3x(x - 3) \\ {x}^{2} - 6x + 9 + 3x = 3 {x}^{2} - 9x \\ 2 {x}^{2} - 6x - 9 = 0 \\ D = 36 + 72 = 108 \\ x_1 = \frac{ 6 + \sqrt{108} }{4} = \frac{6 + 6 \sqrt{2} }{4} = \frac{3 + 3 \sqrt{2} }{2 } \\ x_2 = \frac{3 - 3 \sqrt{2} }{2}$

Answer 2

Ответ:21

Объяснение:

Получится 21 потому что 3*3=9+3=12=3*3=9=12+9=21

Answer 3

Let's solve the given equation step by step.

Starting with the equation: (x - 3)² + 3x = 3x(x - 3)

Expanding the square: (x² - 6x + 9) + 3x = 3x² - 9x

Simplifying and collecting like terms: x² - 6x + 9 + 3x = 3x² - 9x

Combining like terms on both sides: x² - 6x + 3x - 3x² = -9x - 9

Rearranging the terms: x² - 3x² - 6x + 3x + 9x = -9

Simplifying further: -2x² + 6x = -9

Dividing the entire equation by -1 to simplify the leading coefficient: 2x² - 6x = 9

Moving all terms to one side to set the equation to zero: 2x² - 6x - 9 = 0

Now, we can solve this quadratic equation. We can either use factoring, completing the square, or the quadratic formula. In this case, let's use the quadratic formula:

The quadratic formula states that for an equation in the form ax² + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / (2a)

For our equation, a = 2, b = -6, and c = -9. Plugging in these values, we get:

x = (-(-6) ± √((-6)² - 4 * 2 * -9)) / (2 * 2)

Simplifying: x = (6 ± √(36 + 72)) / 4 x = (6 ± √108) / 4 x = (6 ± √(36 * 3)) / 4 x = (6 ± 6√3) / 4

Now, we can simplify further: x = (3 ± 3√3) / 2

So the solutions to the equation (x - 3)² + 3x = 3x(x - 3) are: x = (3 + 3√3) / 2 x = (3 - 3√3) / 2