Question

8cos90градусов-7cos180градусов+3sin270градусов

Answer 1

$8Cos90^{o}-7Cos180^{o} +3Sin270^{o}=8*0-7*(-1)+3*(-1)=0+7-3=4$

Answer 2

cos90°=0;

cos180°= -1;

sin270°= -1.

Это табличные значения...

8cos90°- 7cos180°+3sin270°= 8×0-7×(-1)+3(-1)= 0+7-3= 4.

ОТВЕТ: 4.

Answer 3

To calculate the values of trigonometric functions at specific angles, we use the following standard values:

• cos(90 degrees) = 0
• cos(180 degrees) = -1
• sin(270 degrees) = -1

Let's substitute these values into the given expression:

8 * cos(90 degrees) - 7 * cos(180 degrees) + 3 * sin(270 degrees)

= 8 * 0 - 7 * (-1) + 3 * (-1)

= 0 + 7 - 3

= 4

So, the value of the expression is 4.