Question

(4х-3)×(4x+3)-(4х-1)=3х​

Answer 1

Ответ:

4х^2+12х-12х-9-4х-1-3х=0

4х^2-7х-8=0

х1=8. х2=(-1)

Answer 2

Let's simplify the given expression step by step:

(4x - 3) × (4x + 3) - (4x - 1) = 3x

First, let's apply the distributive property to expand the left side of the equation:

(4x - 3) × (4x + 3) = 4x × 4x + 4x × 3 - 3 × 4x - 3 × 3 = 16x^2 + 12x - 12x - 9 = 16x^2 - 9

Now, our equation becomes:

(16x^2 - 9) - (4x - 1) = 3x

Next, let's combine the constants on the left side:

16x^2 - 9 - 4x + 1 = 3x

Simplify further:

16x^2 - 4x - 8 = 3x

To get the equation in standard form, move all terms to the left side:

16x^2 - 4x - 8 - 3x = 0

Now, we have a quadratic equation:

16x^2 - 7x - 8 = 0

To solve this quadratic equation, we can either factor it or use the quadratic formula:

The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

In our case, a = 16, b = -7, and c = -8.

Using the quadratic formula:

x = [7 ± √((-7)^2 - 4 * 16 * -8)] / 2 * 16 x = [7 ± √(49 + 512)] / 32 x = [7 ± √561] / 32

The two solutions for x are:

1. x = (7 + √561) / 32
2. x = (7 - √561) / 32

These are the final solutions for the equation.