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Помогите пожалуйста!!! 1. Приведите одночлен к стандартному виду: 10 × ссс × 0.5 × b3b². 2. Выполнить умножение многочлена (2d + 1) на многочлен (3 - n). 3. Разложите на множители: 4х² - 9у⁴. 4. Представьте многочлен в виде квадрата разности: 16х⁴ - 40х²у³ + 25у^6. 5. Представьте в виде многочлена в стандартном виде: (3п - 2)×(4n + 1). 5. Решите систему уравнений: {x - 2y = 3 {12x + y = 11p.s. в задании №4 цифра со знаком ^6 является степенью. p.s.s.в задании №5 уравнения объединены одной фигурное скобкойзаранее огромное спасибо! ​ Смотреть ответ petrovamasha92 petrovamasha92 Объяснение: 2: (2b + 1)(3 - n) = 6b - 2bn + 3 - n 3:(2x- 3y ^2)(2х + 3у^2) 4:(4х^2 - 5y^3)^2 5:(3 n - 2)(4n + 1) =12n ^2 + 3n- 8n - 2 = 12n ^2 - 5n - 2 5: {x = 3 + 2y {12(3 + 2y)+ y= 11 36 + 24y + y = 11 25y = - 25 y = - 1 x = 1 Новые вопросы в Алгебра 3(x-2)=x+2 помогите решыть розвʼяжіть систему рівнянь х-у=5 х+у=1 А.(-2;3) Б.(6;1) В.(-2;3) Г.(3;-2) Помогите пожалуйста. 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Answer 1

Давайте по порядку решим ваши математические задачи:

1. Приведем одночлен к стандартному виду: 10 × ссс × 0.5 × b3b². Сначала упростим выражение: 10 × ссс × 0.5 × b3b² = 5ccc * b³b² = 5c^(3+1) * b^(3+2) = 5c⁴b⁵.

2. Выполним умножение многочлена (2d + 1) на многочлен (3 - n). Для умножения многочленов применим правило распределения (FOIL): (2d + 1)(3 - n) = 2d * 3 + 2d * (-n) + 1 * 3 + 1 * (-n) = 6d - 2dn + 3 - n.

3. Разложим на множители: 4х² - 9у⁴. Мы имеем разность квадратов, поэтому можем применить формулу: a² - b² = (a + b)(a - b). 4х² - 9у⁴ = (2x)² - (3y²)² = (2x + 3y²)(2x - 3y²).

4. Представим многочлен в виде квадрата разности: 16х⁴ - 40х²у³ + 25у⁶. Мы видим квадрат разности (a² - b²) в первых двух членах, но последний член у нас уже в квадрате. Применим формулу квадрата разности для первых двух членов: 16х⁴ - 40х²у³ + 25у⁶ = (4x² - 5y³)².

5. Представим в виде многочлена в стандартном виде: (3п - 2) × (4n + 1). Произведение многочленов: (3п - 2) × (4n + 1) = 12pn + 3п - 8n - 2.

Теперь решим систему уравнений:

{ x - 2y = 3 { 12x + y = 11

Можем использовать метод подстановки или метод сложения/вычитания.

Метод сложения/вычитания:

1. Умножим первое уравнение на 12, чтобы коэффициенты у x в обоих уравнениях были одинаковыми и мы смогли сложить их. 12(x - 2y) = 12 * 3 12x - 24y = 36

2. Теперь сложим это уравнение с вторым уравнением, чтобы устранить переменную y. 12x - 24y + y = 36 + 11 12x - 23y = 47

3. Теперь выразим x: 12x = 47 + 23y x = (47 + 23y) / 12

4. Подставим значение x в первое уравнение и решим для y: (47 + 23y) / 12 - 2y = 3 Упростим уравнение: 47 + 23y - 24y = 36 -y = 36 - 47 y = -11

5. Теперь найдем x, подставив значение y в любое из первоначальных уравнений, например, во второе: 12x + (-11) = 11 12x = 11 + 11 12x = 22 x = 22 / 12 x = 11 / 6

Таким образом, решение системы уравнений: x = 11/6, y = -11.

По поводу вашего нового вопроса "3(x-2)=x+2", это уравнение с одной переменной. Давайте решим его:

3(x - 2) = x + 2

1. Раскроем скобку, применяя распределительное свойство: 3x - 6 = x + 2

2. Перенесем все члены с x на одну сторону уравнения, а числовые члены на другую: 3x - x = 2 + 6

3. Упростим уравнение: 2x = 8

4. Разделим обе стороны на 2, чтобы найти значение x: x = 8 / 2 x = 4

Ответ: x = 4.

И на последний вопрос "розвʼяжіть систему рівнянь х-у=5 х+у=1".

1. Мы можем решить эту систему методом сложения/вычитания.

{ x - у = 5 { x + у = 1

2. Сложим оба уравнения, чтобы устранить переменную у: x - у + x + у = 5 + 1 2x = 6

3. Разделим обе стороны на 2, чтобы найти значение x: x = 6 / 2 x = 3

4. Теперь, чтобы найти значение у, подставим значение x в любое из первоначальных уравнений, например, во второе: 3 + у = 1

5. Выразим у: у = 1 - 3 у = -2

Таким образом, решение системы уравнений: x = 3, у = -2. Ответ: Г.(3;-2).