Question

{у = х + 2} {у - 2x = 3}.​

Answer 1

Здравствуйте, Gavriluknasta38!

Если это система уравнений, то решим её либо методом подстановки, либо методом сложения.

Решение системы уравнений (метод подстановки):

$\tt \left \{ {{y=x+2} \atop {y-2x=3}} \right. \Rightarrow \Big(x+2\Big)-2x=3 \Rightarrow x+2-2x=3\Rightarrow -x=1\Rightarrow \bf x=-1$

$\bf \Rightarrow y=-1+2 \Rightarrow y=-\Big(1-2\Big) \Rightarrow y=-\Big(-1\Big) \Rightarrow y=1$

Окончательный ответ:

Данный ответ системы уравнений - "x = -1;  y = 1".

С Уважением, NeNs07.

Answer 2

To solve the system of equations, let's find the values of x and y that satisfy both equations.

Equation 1: y = x + 2

Equation 2: y - 2x = 3

We can solve this system of equations by substitution or elimination method. Let's use the elimination method.

Multiply Equation 1 by 2 to make the coefficients of x in both equations equal:

2y = 2x + 4 (Equation 1)

Now we have the following system of equations:

2y = 2x + 4 (Equation 1) y - 2x = 3 (Equation 2)

Now, subtract Equation 2 from Equation 1:

2y - (y - 2x) = 2x + 4 - 3

Simplifying the equation:

2y - y + 2x = 2x + 1

Combine like terms:

y + 2x = 2x + 1

Subtract 2x from both sides:

y = 1

Now that we have the value of y, we can substitute it back into one of the original equations to find the value of x.

Let's substitute y = 1 into Equation 1:

1 = x + 2

Subtract 2 from both sides:

x = -1

Therefore, the solution to the system of equations is x = -1 and y = 1.