Question

(x-5)^2-(x-5)+2=0 СРОЧНОО

Answer 1

Ответ:

(х - 5)^2 - х^2 = 0

(х - 5 - х)*(х - 5 + х) = 0

-5*(2х - 5) = 0

2х - 5 = 0

2х = 5

х = 2,5

Ответ: 2,5

Объяснение:

Правильно

Answer 2

Ответ:

(x-5)^2-(x-5)+2=0

x^2-10x+25-x+5+2=0

x^2-11x+32=0

D=121-128=-7

корней нет

Объяснение:

Answer 3

To solve the quadratic equation, we can first simplify it and then find the solutions for 'x':

Given equation: (x - 5)^2 - (x - 5) + 2 = 0

Step 1: Expand the square term (x - 5)^2 (x - 5)^2 = (x - 5)(x - 5) = x^2 - 5x - 5x + 25 = x^2 - 10x + 25

Step 2: Replace the (x - 5)^2 in the original equation with its expanded form: x^2 - 10x + 25 - (x - 5) + 2 = 0

Step 3: Combine like terms: x^2 - 10x + 25 - x + 5 + 2 = 0

Step 4: Simplify: x^2 - 11x + 32 = 0

Now, we have a quadratic equation in standard form (ax^2 + bx + c = 0) with a = 1, b = -11, and c = 32.

Step 5: Solve for 'x' using the quadratic formula: The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

Substituting the values: x = (11 ± √((-11)^2 - 4 * 1 * 32)) / 2 * 1 x = (11 ± √(121 - 128)) / 2 x = (11 ± √(-7)) / 2

Since the discriminant (b^2 - 4ac) is negative (-7), the quadratic equation has no real solutions. Instead, it has two complex solutions:

x = (11 + √7i) / 2 x = (11 - √7i) / 2

Note: 'i' represents the imaginary unit (√(-1)).

So, the solutions for the given equation are complex numbers:

x = (11 + √7i) / 2 and x = (11 - √7i) / 2