Question

Log 7 (х - 2) ≤ 0 .............

Answer 1

Ответ:

Вот думаю так удачи тебе

Answer 2

To solve the inequality $\log_7(x - 2) \leq 0$, we need to find the values of $x$ that satisfy this inequality. Remember that the logarithm function with a base greater than 1 is increasing, so $\log_7(x - 2) \leq 0$ means that $x - 2$ must be less than or equal to 1 in order for the logarithm to be less than or equal to 0.

So, we have:

$x - 2 \leq 1$

Now, let's solve for $x$:

$x \leq 1 + 2$

$x \leq 3$

Therefore, the solution to the inequality $\log_7(x - 2) \leq 0$ is $x \leq 3$. This means that any value of $x$ less than or equal to 3 will satisfy the inequality.