Question

X²+4x-5​

Answer 1

Ответ:

5 и -1

от минус одного черти до + бесконечности

------------(минус 1 )-/-/-/-/-/-/-/--/-0-/--/-/-/-/-/-/--/-/-/-/-/5/-/-/-/-/-/--//+бесконечность

(-1;5)u(5;+бесконечности)

Объяснение:

D=b2-4ac

D=16-4*1*(-5)=36 (в корне)= 6

x1/2= 4+/-6/2 = 5 и -1

Answer 2

The expression you provided, x² + 4x - 5, is a quadratic polynomial. To simplify or manipulate it further, you can factorize it, find its roots, or evaluate it for specific values of x. Let's go through these steps:

1. Factorization: To factorize the quadratic expression, we need to find two binomials whose product gives us the original expression. The factors can be obtained by considering two numbers whose sum is equal to the coefficient of the x term (4) and whose product is equal to the constant term (-5). Let's find these numbers:

The factors of -5 are: -5 * 1 -1 * 5

Among these pairs, the sum of -1 and 5 is equal to 4, which matches the coefficient of the x term. Therefore, we can write the expression as:

x² + 4x - 5 = (x - 1)(x + 5)

2. Finding the roots: The roots of the quadratic expression can be determined by setting it equal to zero and solving for x. Using the factored form from the previous step:

(x - 1)(x + 5) = 0

Setting each factor equal to zero:

x - 1 = 0 or x + 5 = 0

Solving for x in each equation:

x = 1 or x = -5

So, the roots of the quadratic expression x² + 4x - 5 are x = 1 and x = -5.

3. Evaluating the expression: If you want to evaluate the expression for specific values of x, you can substitute those values into the expression. For example, let's evaluate it for x = 2:

x² + 4x - 5 = (2)² + 4(2) - 5 = 4 + 8 - 5 = 12 - 5 = 7

So, when x = 2, the expression x² + 4x - 5 evaluates to 7.