Question

{ х − 3y = 8; 2х − у = 6.

Answer 1

Ответ на фотографии

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Answer 2

It looks like you've provided a system of two linear equations in two variables, x and y. The system can be written as:

1. $x - 3y = 8$
2. $2x - y = 6$

To solve for the values of x and y that satisfy both equations, you can use various methods such as substitution or elimination. Let's solve it using the elimination method:

Step 1: Multiply the second equation by 3 to make the coefficients of y the same and then subtract it from the first equation to eliminate y:

$3 \cdot (2x - y) = 3 \cdot 6$ $6x - 3y = 18$

Subtracting this equation from the first equation: $x - 3y - (6x - 3y) = 8 - 18$ $x - 3y - 6x + 3y = -10$ $-5x = -10$

Step 2: Divide both sides by -5 to solve for x: $x = 2$

Now that we have the value of x, we can substitute it back into either of the original equations to solve for y. Let's use the second equation:

$2x - y = 6$ $2 \cdot 2 - y = 6$ $4 - y = 6$

Step 3: Subtract 4 from both sides to solve for y: $-y = 2$

Step 4: Multiply both sides by -1 to solve for y: $y = -2$

So, the solution to the system of equations is $x = 2$ and $y = -2$. This means that the point (2, -2) is the solution that satisfies both equations in the system.