Question

Cos⁡(π/4-β)∙cos⁡(π/4+β) sin⁡β=1

Answer 1

Ответ:

sin⁡β=1  в точке п/2

cos⁡(π/4-п/2)∙cos⁡(π/4+п/2)=cos⁡(-π/4)∙cos⁡(3π/4)=√2/2*(-√2/2)=-1/2

Все.

Я Оля Барсова)

Answer 2

The equation you've provided seems to be incorrect. The equation you've written is:

$\cos\left(\frac{\pi}{4} - \beta\right) \cdot \cos\left(\frac{\pi}{4} + \beta\right) \cdot \sin(\beta) = 1$

However, this equation is not true in general. If you multiply out the two cosine terms, you'll end up with a more complex expression involving both cosine and sine terms, and it won't simplify to 1.

If you have a different equation or if there's a mistake in the equation you've written, please provide more context or correct the equation so that I can help you more accurately.