Question

1,5x-0,4y=320,4x+1,4y=1​

Answer 1

Ответ:

1,5x-0,4y-32=0

15x-4y-320=0

1,4y=1-0,4

1,4y=-0,6

y=3:7

Answer 2

It looks like you have a system of two linear equations with two variables:

1. $1.5x - 0.4y = 320$
2. $0.4x + 1.4y = 1$

To solve this system of equations, you can use various methods, such as substitution, elimination, or matrix methods. Let's use the elimination method here:

Step 1: Multiply the second equation by 3.75 (which is 1.5 divided by 0.4) to make the coefficients of $y$ in both equations the same:

$3.75 \cdot (0.4x + 1.4y) = 3.75 \cdot 1$
$1.5x + 5.25y = 3.75$

Step 2: Now, subtract the first equation from this new equation to eliminate $y$:

$(1.5x + 5.25y) - (1.5x - 0.4y) = 3.75 - 320$
$5.25y + 0.4y = -316.25$
$5.65y = -316.25$
$y = -316.25 / 5.65$
$y \approx -55.973$

Step 3: Now that you have the value of $y$, you can substitute it back into either of the original equations to solve for $x$. Let's use the first equation:

$1.5x - 0.4(-55.973) = 320$
$1.5x + 22.3892 = 320$
$1.5x = 297.6108$
$x = 297.6108 / 1.5$
$x \approx 198.407$

So, the solution to the system of equations is approximately $x \approx 198.407$ and $y \approx -55.973$.