Question

-b(b+2)+(b+3)(b-3) при b=1/2

Answer 1

Ответ:

решение смотри на фотографии

Объяснение:

Answer 2

To evaluate the expression -b(b+2)+(b+3)(b-3) at b = 1/2, we substitute b with 1/2 and perform the calculations:

First, let's substitute b with 1/2:

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-(1/2)((1/2)+2)+((1/2)+3)((1/2)-3)

Simplifying the expression:

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-(1/2)(5/2)+(7/2)(-5/2)

Now, let's multiply each term:

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-5/4 - (35/4)

Combining the terms:

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-5/4 - 35/4

To add or subtract fractions, we need a common denominator. In this case, the common denominator is 4:

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(-5 - 35) / 4

Calculating the numerator:

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-40 / 4

Simplifying the expression:

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-10

Therefore, when b = 1/2, the expression -b(b+2)+(b+3)(b-3) evaluates to -10.