Question

(а-6) (а+4) < (а+2) (а-4)​

Answer 1

Ответ:

решение смотри на фотографии

Объяснение:

Answer 2

(а - 6) (а + 4) < (а + 2) (а - 4)

Ответ:

- 24 < - 8

Answer 3

To solve the inequality $(a-6)(a+4) < (a+2)(a-4)$, we can start by expanding both sides of the inequality:

Left side: $(a-6)(a+4) = a^2 + 4a - 6a - 24 = a^2 - 2a - 24$

Right side: $(a+2)(a-4) = a^2 - 4a + 2a - 8 = a^2 - 2a - 8$

Now, we have: $a^2 - 2a - 24 < a^2 - 2a - 8$

Subtracting $a^2 - 2a - 8$ from both sides gives: $-24 < -8$

This is true for all values of $a$, since -24 is indeed less than -8. Therefore, the inequality $(a-6)(a+4) < (a+2)(a-4)$ holds true for all real values of $a$.