Question

2-5y=5(1-2y) 2(5-8x)=-4(4x+3)

Answer 1

Данный ответ представлен фотографией.

Answer 2

It looks like you've provided two equations with variables. You might want to solve for the values of the variables in each equation. Let's go through each equation step by step.

Equation 1: $2 - 5y = 5(1 - 2y)$

Step 1: Distribute the 5 on the right side of the equation: $2 - 5y = 5 - 10y$

Step 2: Combine like terms on both sides of the equation: $2 - 5 = -10y - 5y$ $-3 = -15y$

Step 3: Solve for $y$ by dividing both sides by -15: $y = \frac{-3}{-15} = \frac{1}{5}$

So, the solution for Equation 1 is $y = \frac{1}{5}$.

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Equation 2: $2(5 - 8x) = -4(4x + 3)$

Step 1: Distribute the coefficients on both sides of the equation: $10 - 16x = -16x - 12$

Step 2: Add $16x$ to both sides of the equation to isolate the constants: $10 = -12$

Since the equation $10 = -12$ is not true, this means that there is no valid solution for Equation 2.

To summarize, the solution for Equation 1 is $y = \frac{1}{5}$, and Equation 2 has no valid solution.