Question

А:(а+3)(а-5)>(а-7)(а+5)=

Answer 1

Відповідь:

a²-5a+3a-15<a²+5a-7a-35(а² исчезнет)

-5а+3а-5а+7а<15-35

О<20

Пояснення:

Нет решения так как отрицательные числа

Answer 2

To solve the inequality $(a+3)(a-5) > (a-7)(a+5)$, we can start by expanding both sides and simplifying the expression:

On the left side: $(a+3)(a-5) = a^2 - 5a + 3a - 15 = a^2 - 2a - 15$

On the right side: $(a-7)(a+5) = a^2 + 5a - 7a - 35 = a^2 - 2a - 35$

Now, the inequality becomes: $a^2 - 2a - 15 > a^2 - 2a - 35$

Notice that the $a^2$ and the $-2a$ terms cancel out on both sides of the inequality:

$-15 > -35$

Now, it's clear that this inequality is true because any negative number (in this case, -15) is indeed greater than a more negative number (in this case, -35).

So, the solution to the inequality $(a+3)(a-5) > (a-7)(a+5)$ is that it's true for all real values of 'a'. In other words, the inequality holds for any real number you choose for 'a'.