Question

(x+1)(x-3)-(x-4)(x+4)>3

Answer 1

Объяснение:

$(x+1)*(x-3)-(x-4)*(x+4)>3\\x^2-2x-3-(x^2-16)>3\\x^2-2x-3-x^2+16>3\\-2x+13>3\\2x$

Ответ: x∈(-∞;5).

Answer 2

вот тебе ответ смотри на рисунок!!!!!!!!!!!!!!!!!!!

Answer 3

Let's simplify the given inequality step by step:

Given inequality:

(x+1)(x-3) - (x-4)(x+4) > 3

Let's expand both parts of the expression:

(x+1)(x-3) = x^2 - 3x + x - 3 = x^2 - 2x - 3 (x-4)(x+4) = x^2 + 4x - 4x - 16 = x^2 - 16

Substitute these expansions back into the inequality:

(x^2 - 2x - 3) - (x^2 - 16) > 3

Simplify the expression within the parentheses:

x^2 - 2x - 3 - x^2 + 16 > 3

Simplify further:

-2x + 13 > 3

Subtract 13 from both sides:

-2x > -10

Divide by -2 (remember to reverse the inequality since you're dividing by a negative number):

x < 5

So, the solution to the inequality is x < 5.