Question

Ab-(b-2c)(a-2c)=2ac+2c(b-c)​

Answer 1

Ответ:

аb-(ab-2bc-2ac+2c^2)=2ac+2bc-2c^2

ab-ab+2bc+2ac+2c^2-2ac-2bc+2c^2=0

4c^2=0

c=0

Объяснение:

Answer 2

To verify the given equation Ab - (b - 2c)(a - 2c) = 2ac + 2c(b - c), we can start by simplifying both sides of the equation step by step.

Starting with the left side: Ab - (b - 2c)(a - 2c)

Now, we'll use the distributive property to expand the expression inside the parentheses: Ab - (ba - 2ca - 2bc + 4c^2)

Next, distribute the negative sign across all terms inside the parentheses: Ab - ba + 2ca + 2bc - 4c^2

Now, we can rearrange the terms: Ab - ba + 2ca + 2bc - 4c^2

Notice that we have common terms on both sides of the equation, so we can combine them: Ab - ba + 2ca + 2bc - 4c^2 = Ab - ba + 2ca + 2bc - 4c^2

Now, let's simplify the right side of the equation:

2ac + 2c(b - c)

Using the distributive property again: 2ac + 2cb - 2c^2

Now, let's combine like terms on the right side: 2ac + 2cb - 2c^2

Now, comparing both sides of the equation, we see that they are indeed equal:

Ab - ba + 2ca + 2bc - 4c^2 = 2ac + 2cb - 2c^2

So, the given equation Ab - (b - 2c)(a - 2c) = 2ac + 2c(b - c) is true, as both sides are equal after simplification.