Question

(2c²-3c)+1,8-c²-(c²-3c-2,2)​

Answer 1

Ответ:

Объяснение:

(2c²-3c)+1,8-c²-(c²-3c-2,2)=

2c²-3c+1,8-c²-c²+3c+2,2=4

Answer 2

Let's simplify the given expression step by step:

Expression 1: 2c² - 3c + 1

Expression 2: 8 - c² - (c² - 3c - 2.2)

Now, let's simplify Expression 2 by distributing the negative sign:

Expression 2: 8 - c² - c² + 3c + 2.2

Now, combine like terms in Expression 2:

• c² - c² = 0 3c + 2.2 = 3c + 2.2

So, Expression 2 simplifies to:

8 - 0 + 3c + 2.2 = 11.2 + 3c

Now, we can combine Expression 1 and the simplified Expression 2:

(2c² - 3c + 1) + (11.2 + 3c)

Now, combine like terms in the above expression:

2c² - 3c + 1 + 11.2 + 3c

Now, simplify by adding the constants and the coefficients of 'c':

(2c² + 3c - 3c) + (1 + 11.2)

The '3c' and '-3c' terms cancel each other out:

2c² + 1 + 11.2

Now, add the constants:

2c² + 12.2

So, the simplified expression is:

2c² + 12.2