Question

Cos2x-cos2x=cos2x*sin2x​

Answer 1

Ответ:

$x = \frac{\pi k}{4}$,k є Z

Объяснение:

Смотрите фото

Answer 2

Let's simplify the given equation:

cos(2x) - cos(2x) = cos(2x) * sin(2x)

The left side of the equation simplifies to 0 because any number subtracted from itself is 0:

0 = cos(2x) * sin(2x)

Now, we have an equation involving the product of two trigonometric functions. We can solve it by considering two cases:

Case 1: cos(2x) = 0 If cos(2x) = 0, then the right side of the equation becomes 0 regardless of the value of sin(2x). In this case, the equation is satisfied for all values of x.

Case 2: sin(2x) = 0 If sin(2x) = 0, then the right side of the equation becomes 0 regardless of the value of cos(2x). In this case, the equation is also satisfied for all values of x.

So, the equation is satisfied for all values of x, whether cos(2x) = 0 or sin(2x) = 0.