Question

Sin a=0,3 ; П/2<а<П​

Answer 1

Ответ:

sin a = - 0.3 и 3п/2 < a < 2 п

cosa = √(1 - sin²a) = √(1 - (-0,3)²) = √(1 - 0,09) = √0,91= √91/100 = √91/10

tga = sina/cosa = - 0,3 : √91/10 = -3/√91

ctga = - √91 /3

Объяснение:

Answer 2

It seems like you're interested in finding the value of the sine function when the angle 'a' is between π/2 and π (Pi/2 and Pi) and equal to 0.3. To calculate this, you can simply use the sine function. The sine of an angle is the length of the side opposite that angle divided by the hypotenuse in a right triangle. When you say sin(a) = 0.3, it means that:

sin(a) = 0.3

Now, to find the angle 'a' between π/2 and π where sin(a) is approximately equal to 0.3, you can use the inverse sine function (also known as arcsin or sin^-1). So:

a = arcsin(0.3)

To calculate this value, you would use a calculator or software with trigonometric functions, which will give you the angle 'a' in radians.

However, I can't provide the exact numerical result because it depends on the calculator or software you use. But you can input arcsin(0.3) into a calculator or a math software to find the angle 'a' within the specified range.