Question

1) 12х²-х = 0 2) 8х²+6х =0​

Answer 1

Ответ:

Объяснение:

12х²-х = 0

x(12x-1)=0

x=0

12x-1=0

12x=1

x=1/12

8х²+6х =0​

2x(4x+3)=0

x=0

4x= -3

x= -3/4

Answer 2

||||||||||||||||||||||||||||||

Answer 3

To solve the quadratic equations:

1. 12x² - x = 0

2. 8x² + 6x = 0

You can use the quadratic formula:

For a quadratic equation in the form of ax² + bx + c = 0, the quadratic formula is:

x = (-b ± √(b² - 4ac)) / (2a)

Let's solve each equation step by step:

1. 12x² - x = 0

a = 12, b = -1, c = 0

x = (-(-1) ± √((-1)² - 4(12)(0))) / (2(12))

x = (1 ± √(1 - 0)) / 24

x = (1 ± 1) / 24

There are two solutions:

x₁ = (1 + 1) / 24 = 2/24 = 1/12

x₂ = (1 - 1) / 24 = 0/24 = 0

So, the solutions to the first equation are x₁ = 1/12 and x₂ = 0.

2. 8x² + 6x = 0

a = 8, b = 6, c = 0

x = (-6 ± √(6² - 4(8)(0))) / (2(8))

x = (-6 ± √(36 - 0)) / 16

x = (-6 ± √36) / 16

x = (-6 ± 6) / 16

There are two solutions:

x₁ = (-6 + 6) / 16 = 0/16 = 0

x₂ = (-6 - 6) / 16 = -12/16 = -3/4

So, the solutions to the second equation are x₁ = 0 and x₂ = -3/4.