Question

(6-k)(6+k)=(c+8)^2=(7-y)(49+7y+y^2)=

Answer 1

Ответ:

Объяснение:

(6-k)(6+k)=36-k²=-k²+36

(c+8)²=c²+16c+64

(7-y)(49+7y+y²)=7³-y³=343-y³=-y³+343

Answer 2

Let's solve the given equations step by step:

1. (6 - k)(6 + k) = (c + 8)^2

   To simplify this equation, we'll use the difference of squares formula (a^2 - b^2 = (a + b)(a - b)):

   (6^2 - k^2) = (c + 8)^2

   36 - k^2 = (c + 8)^2

2. (7 - y)(49 + 7y + y^2)

   This equation appears to be a quadratic equation. Let's first factor it:

   (7 - y)(49 + 7y + y^2) = (7 - y)(7 + y)^2

Now, we have two equations:

1. 36 - k^2 = (c + 8)^2

2. (7 - y)(7 + y)^2

It's not clear what you want to do with these equations or if you have any specific questions related to them. If you have additional instructions or need further assistance with these equations, please provide more details, and I'll be happy to help.