Question

(2-c) (3-c)≥000000000000

Answer 1

Ответ:

правельно

Объяснение:

Answer 2

The expression you've provided, "(2-c)(3-c)≥000000000000," appears to be a comparison or inequality statement. However, it seems like you've included a large number of zeros on the right side of the inequality sign, which doesn't affect the inequality itself.

To solve the inequality "(2-c)(3-c)≥0," you can follow these steps:

1. Expand the left side of the inequality: (2-c)(3-c) = 6 - 5c + c^2

2. Rewrite the inequality: 6 - 5c + c^2 ≥ 0

3. Rearrange the terms: c^2 - 5c + 6 ≥ 0

4. Factor the quadratic expression: (c - 2)(c - 3) ≥ 0

Now, you have factored the expression, and you can find the solution by examining when the factors are greater than or equal to zero. To do this, you can use a sign chart or consider the intervals where each factor is positive or zero.

The solutions are as follows:

• When (c - 2) and (c - 3) are both greater than or equal to zero:

  • c ≥ 3
  • c ≥ 2

• When (c - 2) and (c - 3) are both less than or equal to zero:

  • c ≤ 3
  • c ≤ 2

• When (c - 2) is greater than or equal to zero, and (c - 3) is less than or equal to zero:

  • c ≥ 2
  • c ≤ 3 (Note: This is the intersection of the two cases above.)

• When (c - 2) is less than or equal to zero, and (c - 3) is greater than or equal to zero:

  • c ≤ 2
  • c ≥ 3 (This case has no valid solutions since it's contradictory.)

So, the valid solution for the inequality (2-c)(3-c) ≥ 0 is: c ≤ 2 or c ≥ 3