Question

(x-2)(x-3)-(x+2)(x-5)=0

Answer 1

Объяснение:

Решение на фотографии

Answer 2

To solve the quadratic equation $(x-2)(x-3) - (x+2)(x-5) = 0$, you can start by expanding and simplifying the equation, and then solve for $x$. Here's how to do it:

1. Expand the expressions:

$(x-2)(x-3) - (x+2)(x-5) = 0$

Expand both terms:

$x^2 - 3x - 2x + 6 - (x^2 - 5x + 2x - 10) = 0$

2. Simplify the equation by combining like terms:

$x^2 - 5x + 6 - x^2 + 3x - 6 = 0$

Now, the $x^2$ terms cancel out, and the $x$ terms also cancel out:

$-5x + 3x = 0$

Simplify further:

$-2x = 0$

3. Solve for $x$ by isolating $x$:

$-2x = 0$

Divide both sides by -2:

$x = 0$

So, the solution to the equation $(x-2)(x-3) - (x+2)(x-5) = 0$ is $x = 0$.