Question

Cos²t+ctg²t×cos²t-ctg²t​

Answer 1

Ответ:

cos2t+c2t3g2os2-st2g2

st*(os2+ct2g2os2-tg2)

st*(os2+cg2os2t2-g2t)

Answer 2

It seems you have an expression involving trigonometric functions that you'd like to simplify. Let's break it down step by step:

The expression is: cos²(t) + cot²(t) * cos²(t) - cot²(t)

First, let's factor out the common term, which is cot²(t):

cot²(t) * (cos²(t) - 1)

Now, we can use the Pythagorean identity for sine and cosine:

sin²(t) + cos²(t) = 1

Rearrange it to isolate cos²(t):

cos²(t) = 1 - sin²(t)

Now, substitute this into our expression:

cot²(t) * (1 - sin²(t) - 1)

Now, simplify further:

cot²(t) * (-sin²(t))

Since cot(t) = 1/tan(t), and tan(t) = sin(t) / cos(t), cot(t) can be expressed as:

cot(t) = cos(t) / sin(t)

Now, replace cot(t) with its equivalent expression:

(cos(t) / sin(t))² * (-sin²(t))

Simplify further by canceling out a sin(t) term:

cos²(t) * (-sin(t))

Finally, you can express it as:

-cos²(t) * sin(t)

So, the simplified expression is: -cos²(t) * sin(t).