Question

17 + 4х ≥ 5 – 7(3 - х) + 2(5 - х)

Answer 1

Ответ:

1. Розкриваємо дужки

2. Переносимо все в ліву частину

3. Зводимо подібні доданки

4. Робимо відповідні дії

5. Записуємо відповідь

Объяснение:

Answer 2

To solve the inequality $17 + 4x \geq 5 - 7(3 - x) + 2(5 - x)$, follow these steps:

1. First, distribute the constants on the right side of the inequality:

$17 + 4x \geq 5 - 21 + 7x + 10 - 2x$

2. Combine like terms on the right side:

$17 + 4x \geq -16 + 5x + 10$

3. Next, move all the x terms to one side of the inequality by subtracting $5x$ from both sides:

$17 - 5x + 4x \geq -16 + 10$

4. Simplify the x terms on the left side:

$17 - x \geq -6$

5. To isolate x, subtract 17 from both sides:

$-x \geq -6 - 17$

$-x \geq -23$

6. Finally, to solve for x, multiply both sides by -1, remembering that when you multiply or divide by a negative number, the inequality sign flips:

$x \leq 23$

So, the solution to the inequality is $x \leq 23$.