Question

Sin(пи+альфа)*cos(пи-альфа)/ctg(3пи/альфа-2)

Answer 1

Ответ:

Объяснение:

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Answer 2

Let's simplify the expression step by step:

1. First, let's simplify the trigonometric functions:

   • sin(π + α) = -sin(α) (because sine is negative in the second and third quadrants, and π + α is in the second quadrant).
   • cos(π - α) = -cos(α) (because cosine is negative in the second and third quadrants, and π - α is in the third quadrant).
   • ctg(3π/α - 2) is the cotangent of an angle, and I'll leave it in that form for now.

So the expression becomes:

(-sin(α) * -cos(α)) / ctg(3π/α - 2)

2. Now, let's simplify the numerator:

   -sin(α) * -cos(α) = sin(α) * cos(α)

3. The denominator remains the same:

   ctg(3π/α - 2)

So, the simplified expression is:

(sin(α) * cos(α)) / ctg(3π/α - 2)

Please note that the expression still contains the cotangent function ctg(3π/α - 2), and you might want to further simplify or evaluate it depending on the specific values of α.