Question

A) 3a-10a³-6a=б) 6х-(4х+2)(х-1)в) (a-6) ²+41​

Answer 1

Ответ:

а) -3а-10а²

б) -4х²+8х+2

в) а²-12а+77

Answer 2

Let's simplify each expression:

A) $3a - 10a^3 - 6a$

Combine like terms:

$-10a^3 + (3a - 6a)$

Combine $3a$ and $-6a$:

$-10a^3 - 3a$

B) $6x - (4x + 2)(x - 1)$

Distribute the terms inside the parentheses:

$6x - (4x^2 - 4x + 2x - 2)$

Combine like terms:

$6x - 4x^2 + 6x - 2$

Combine $6x$ terms:

$-4x^2 + 12x - 2$

C) $(a - 6)^2 + 41$

Expand the square:

$(a - 6)(a - 6) + 41$

Use FOIL (First, Outer, Inner, Last) to multiply:

$a^2 - 6a - 6a + 36 + 41$

Combine like terms:

$a^2 - 12a + 77$

So, the simplified expressions are:

A) $-10a^3 - 3a$

B) $-4x^2 + 12x - 2$

C) $a^2 - 12a + 77$