Question

7y^2-61y=0 y1=?, y2=?

Answer 1

y1=0

y2=61/7= 8 5/7

...............

Answer 2

Вот твой ответ на вопрос
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И сделай этот ответ лучшим

Answer 3

To find the values of y that satisfy the equation 7y^2 - 61y = 0, you can use the quadratic formula:

y = (-b ± √(b² - 4ac)) / (2a)

In this case, the coefficients are: a = 7 b = -61 c = 0

Plugging these values into the quadratic formula:

y1 = (-(-61) + √((-61)² - 4 * 7 * 0)) / (2 * 7) y1 = (61 + √(61² - 0)) / 14 y1 = (61 + √(3721)) / 14 y1 = (61 + 61) / 14 y1 = 122 / 14 y1 = 61 / 7

y2 = (-(-61) - √((-61)² - 4 * 7 * 0)) / (2 * 7) y2 = (61 - √(61² - 0)) / 14 y2 = (61 - √(3721)) / 14 y2 = (61 - 61) / 14 y2 = 0 / 14 y2 = 0

So, the solutions for y are: y1 = 61/7 y2 = 0