Question

(x²-3x-5)(x²-3x+1)=-5​

Answer 1

Ответ:  x=0

x=-1

x=3

x=4

инфа 10000

Answer 2

To solve the equation $(x^2-3x-5)(x^2-3x+1)=-5$, you can first expand the left-hand side of the equation and then simplify the resulting equation to find the values of $x$.

Let's expand the left-hand side:

$(x^2-3x-5)(x^2-3x+1)$

$= x^2(x^2-3x+1) - 3x(x^2-3x+1) - 5(x^2-3x+1)$

$= x^4 - 3x^3 + x^2 - 3x^3 + 9x^2 - 3x - 5x^2 + 15x - 5$

$= x^4 - 6x^3 + 5x^2 + 12x - 5$

Now our equation becomes:

$x^4 - 6x^3 + 5x^2 + 12x - 5 = -5$

$x^4 - 6x^3 + 5x^2 + 12x = 0$

Now, we can solve this equation by factoring out common terms. Factoring out an $x$ gives:

$x(x^3 - 6x^2 + 5x + 12) = 0$

Setting each factor to 0 gives us potential solutions:

1. $x = 0$
2. $x^3 - 6x^2 + 5x + 12 = 0$

The second equation is a cubic equation that can be solved using numerical methods or analytical techniques like the Rational Root Theorem, synthetic division, or the cubic formula.

So, the solutions for $x$ are $x = 0$ and the solutions of the cubic equation $x^3 - 6x^2 + 5x + 12 = 0$.