Question

Y=3-xy=-2​

Answer 1

Ответ:

3-х=3-(-2)

-х=2

х=-2

Объяснение:

раскрываем скобки и изменяем знаки

Answer 2

It appears that you have provided two equations, but you didn't specify what you'd like to do with them. If you're looking to solve this system of equations for the values of x and y that satisfy both equations simultaneously, you can use the method of substitution or elimination.

Let's start with the equations:

1. y = 3 - x
2. -xy = -2

First, we can substitute the expression for y from the first equation into the second equation:

-x(3 - x) = -2

Now, distribute the -x on the left side of the equation:

-3x + x^2 = -2

Now, move all terms to one side of the equation to set it equal to zero:

x^2 - 3x + 2 = 0

This is a quadratic equation. You can solve it by factoring or using the quadratic formula. In this case, it factors easily:

(x - 2)(x - 1) = 0

Now, set each factor equal to zero and solve for x:

1. x - 2 = 0 => x = 2
2. x - 1 = 0 => x = 1

So, there are two possible values of x: x = 1 and x = 2.

Now that we have the values of x, we can find the corresponding values of y using the first equation:

For x = 1: y = 3 - 1 = 2

For x = 2: y = 3 - 2 = 1

So, the solution to the system of equations is (x, y) = (1, 2) and (2, 1).