Question

(x²-2x+3)(x²-2x+4)=12​

Answer 1

Ответ:

$x1 = 0 \: \: \: x2 = 2$

Объяснение:

Я ХЗ КАК СДЕЛАТЬ ЧТО 1 И 2 В НИЩУ БЫЛИ

Answer 2

To solve the equation $(x^2 - 2x + 3)(x^2 - 2x + 4) = 12$, you can follow these steps:

1. Expand the left side of the equation:

   $(x^2 - 2x + 3)(x^2 - 2x + 4) = x^4 - 2x^3 + 3x^2 - 2x^3 + 4x^2 - 6x + 3x^2 - 6x + 12$

2. Combine like terms:

   $x^4 - 4x^3 + 10x^2 - 12x + 12 = 12$

3. Subtract 12 from both sides of the equation to move all terms to one side:

   $x^4 - 4x^3 + 10x^2 - 12x = 0$

4. Factor out common terms if possible:

   $x(x^3 - 4x^2 + 10x - 12) = 0$

5. Now, we need to solve the equation $x^3 - 4x^2 + 10x - 12 = 0$. Unfortunately, this cubic equation doesn't have simple rational solutions. You can either use numerical methods, such as graphing or a numerical solver, to find approximate solutions or factor it further if possible. However, the cubic equation's factors are not immediately apparent, so a numerical approach might be more practical.