Question

-2x + 3y = 8,4x+5y=6.​

Answer 1

-2x + 3y = 8 (×2)

{-4x+6y=16

{4x+5y=6

Прибавляем:

11у=22

у=2

4х+10=6

4х=-4

х=-1

Ответ: (-1;2)

Answer 2

To solve the system of linear equations:

1. -2x + 3y = 8
2. 4x + 5y = 6

You can use either the substitution method or the elimination method. I'll demonstrate the elimination method.

First, we'll multiply both sides of equation 1 by 2 to make the coefficients of x in both equations cancel out when added together:

1. -4x + 6y = 16

Now, we have the system:

1. -4x + 6y = 16
2. 4x + 5y = 6

Next, add the two equations together:

(-4x + 6y) + (4x + 5y) = 16 + 6

The -4x and 4x terms cancel out, leaving you with:

11y = 22

Now, divide both sides by 11 to solve for y:

11y/11 = 22/11

y = 2

Now that you have found the value of y, you can substitute it back into either equation 1 or 2 to solve for x. Let's use equation 1:

-2x + 3(2) = 8

-2x + 6 = 8

Subtract 6 from both sides:

-2x = 2

Now, divide both sides by -2 to solve for x:

-2x / -2 = 2 / -2

x = -1

So, the solution to the system of equations is:

x = -1 y = 2