Question

2) (6 x-9y=88,5, 5x+3y=47,5;​

Answer 1

Ответ: 6 x-9y=88,5                                  5x+3y=47,5  

            6x-9y=88,5=0                             5x+3y-47,5=0  

              6x-9y=88,5=0                             50x+30y-475=0

            60x-90y-885=0                             10x+6y-95=0

            4x-6y-59=0                                      

                                                                 

Объяснение: Вот

Answer 2

It looks like you've provided a system of two linear equations with two variables:

1. 6x - 9y = 88
2. 5x + 3y = 47

You can solve this system of equations using various methods, such as substitution, elimination, or matrix methods. Let's use the elimination method to solve this system:

First, you can multiply the second equation by 3 to make the coefficients of y in both equations cancel out when added:

1. 6x - 9y = 88
2. 15x + 9y = 141

Now, add the two equations together to eliminate the y variable:

(6x - 9y) + (15x + 9y) = 88 + 141

Combine like terms:

21x = 229

Now, divide both sides by 21 to solve for x:

x = 229 / 21

x ≈ 10.9048 (rounded to four decimal places)

Now that you've found the value of x, you can substitute it back into either equation to find the value of y. Let's use the second equation:

5x + 3y = 47 5(10.9048) + 3y = 47 54.524 + 3y = 47

Subtract 54.524 from both sides:

3y = 47 - 54.524 3y = -7.524

Now, divide both sides by 3 to solve for y:

y ≈ -7.524 / 3 y ≈ -2.508 (rounded to three decimal places)

So, the solution to the system of equations is approximately:

x ≈ 10.9048 y ≈ -2.508