Question

5(х – 3) + 2 = 3 (х – 4) + 2х ‒ 1 ​

Answer 1

Объяснение:

5(x-3)+2=3(x-4)+2x-1

5x-15+2=3x-12+2x-1

5x-3x-2x=-12-1+15-2

0x=0

x=∅ (нет корней, так как на ноль делить нельзя)

Answer 2

5(x-3)+2=3(x-4)+2x-1

5x-15+2=3x-12+2x-1

5x-3x-2x=-12-1+15-2

0x=0

x=0

Answer 3

Let's solve the given equation:

$5(x - 3) + 2 = 3(x - 4) + 2x - 1$

First, distribute the numbers outside the parentheses:

$5x - 15 + 2 = 3x - 12 + 2x - 1$

Now, combine like terms on both sides of the equation:

$5x - 13 = 5x - 13$

Notice that the $5x$ terms cancel out when subtracted from both sides. The resulting equation is $-13 = -13$, which is a true statement.

Since the equation is true, it means that the solution is all real numbers. In other words, any value of $x$ will satisfy the equation. This type of equation is called an identity.